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Geometry Concepts and Questions : Number of Triangles or Circles Formed from n Points – Must Practice Set for CAT, XAT & Other MBA Exams

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Geometry Concepts and Questions : Number of Triangles or Circles Formed from n Points – Must Practice Set for CAT, XAT & Other MBA Exams

Number of Triangles or Circles Formed from n Points – Geometry Concept

🔺 ⭕Number of Triangles or Circles Formed from n Points – Geometry Concept

In geometry, a triangle is formed by choosing 3 non-collinear points. The concept of how many Triangles or Circles can be formed from \( n \) points is an important topic for exams like CAT, XAT, SSC CGL, NTSE, and other aptitude tests.

1. When No Three Points Are Collinear

If no three points among \( n \) are collinear, then the number of Triangles or Circles is simply:

\[ \text{Number of Triangles or Circles} = \binom{n}{3} = \frac{n(n-1)(n-2)}{6} \]

Each set of 3 distinct points uniquely determines a triangle.

2. When m Points Are Collinear

If \( m \) out of \( n \) points are collinear, they lie on the same straight line and cannot form a triangle among themselves.

Hence, total Triangles or Circles = Total possible Triangles or Circles − Invalid Triangles or Circles from collinear set:

\[ \binom{n}{3} - \binom{m}{3} \]

3. General Case: Multiple Collinear Groups

If multiple groups of collinear points exist (say sets of sizes \( m_1, m_2, \dots \)), then:

\[ \text{Valid Triangles or Circles} = \binom{n}{3} - \left[\binom{m_1}{3} + \binom{m_2}{3} + \dots \right] \]
Important: If all \( n \) points are collinear, then:
\[ \text{Triangles or Circles} = 0 \]

📌 Examples

Example 1: Out of 10 points, no three are collinear. Then:

\[ \binom{10}{3} = \frac{10 \cdot 9 \cdot 8}{6} = 120 \text{ Triangles or Circles} \]

Example 2: Out of 10 points, 4 are collinear. Then:

\[ \binom{10}{3} - \binom{4}{3} = 120 - 4 = 116 \text{ Triangles or Circles} \]

Example 3: Out of 12 points, two collinear groups of 4 and 3 points. Then:

\[ \binom{12}{3} - \binom{4}{3} - \binom{3}{3} = 220 - 4 - 1 = 215 \text{ Triangles or Circles} \]
Practice Questions
Triangles from n Points – Geometry Practice Questions

🔺 Practice Questions – Triangles Formed from n Points

Click below to reveal answers and step-by-step explanations.



1) Out of 10 points on a plane, 8 are collinear. How many triangles can be formed?

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Answer: 64

Solution: \( \binom{10}{3} - \binom{8}{3} = 120 - 56 = 64 \)

2) Out of 8 points on a plane, 6 are collinear. How many triangles can be formed?

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Answer: 36

Solution: \( \binom{8}{3} - \binom{6}{3} = 56 - 20 = 36 \)

3) If no three of the 14 points on a plane are collinear, how many triangles can be formed?

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Answer: 364

Solution: \( \binom{14}{3} = \frac{14 \cdot 13 \cdot 12}{6} = 364 \)

4) If no three of the 9 points on a plane are collinear, how many triangles can be formed?

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Answer: 84

Solution: \( \binom{9}{3} = \frac{9 \cdot 8 \cdot 7}{6} = 84 \)

5) Out of 7 points on a plane, 3 are collinear. How many triangles can be formed?

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Answer: 34

Solution: \( \binom{7}{3} - \binom{3}{3} = 35 - 1 = 34 \)

6) Out of 12 points on a plane, 5 are collinear. How many triangles can be formed?

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Answer: 206

Solution: \( \binom{12}{3} - \binom{5}{3} = 220 - 10 = 210 \)

7) If all 8 points lie on the same line, how many triangles can be formed?

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Answer: 0

Solution: All points collinear → no triangle possible.

8) Out of 9 points, 3 are collinear. How many triangles can be formed?

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Answer: 83

Solution: \( \binom{9}{3} - \binom{3}{3} = 84 - 1 = 83 \)

9) From 11 points on a plane, 4 are collinear. How many triangles can be formed?

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Answer: 161

Solution: \( \binom{11}{3} - \binom{4}{3} = 165 - 4 = 161 \)

10) Out of 15 points, no three are collinear. How many triangles can be formed?

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Answer: 455

Solution: \( \binom{15}{3} = \frac{15 \cdot 14 \cdot 13}{6} = 455 \)

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