CAT 2025 Slot3 Quant: Ankita walks from A to C through B , and runs back through the same route
March 7, 2026 2026-03-07 15:20CAT 2025 Slot3 Quant: Ankita walks from A to C through B , and runs back through the same route
Type your answer (in minutes):
Speed ratio $W:R = 100:140 = 5:7$. Time ratio for same distance is $7:5$.
Time to walk $BC = 210$ min. Time to run $AB = 210$ min.
$Walk(AB) = 210 \times \frac{7}{5} = 294$ min. $Run(BC) = 210 \times \frac{5}{7} = 150$ min.
Total: $294 + 150 = \mathbf{444}$ min.
Detailed Step-by-Step Solution
Step 1: Understand the Speeds
Let walking speed be $v_w = 5k$ and running speed be $v_r = 1.4 \times 5k = 7k$.
Time taken is inversely proportional to speed for a constant distance: $T \propto \frac{1}{v}$.
Step 2: Use given time data
Given: Time to walk $B \to C = 3$ hrs $30$ mins $= 210$ minutes.
Given: Time to run $B \to A = 3$ hrs $30$ mins $= 210$ minutes.
Step 3: Calculate required segment times
To walk $A \to B$: Since running $BA$ takes $210$ min, walking $AB$ will take $210 \times \frac{7}{5} = 294$ minutes.
To run $B \to C$: Since walking $BC$ takes $210$ min, running $BC$ will take $210 \times \frac{5}{7} = 150$ minutes.
Step 4: Final Calculation
Total time $= \text{Walk}(AB) + \text{Run}(BC)$
Total time $= 294 + 150 = \mathbf{444}$ minutes.