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Geometry Concepts and Questions : Number of Lines from n Points on a Plane – Must Practice Set for CAT, XAT & Other MBA Exams

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Geometry Concepts and Questions : Number of Lines from n Points on a Plane – Must Practice Set for CAT, XAT & Other MBA Exams

Number of Lines from n Points on a Plane – Geometry Concept for CAT/XAT

Number of Lines from n Points on a Plane – Geometry Concept

In geometry, one of the most common problems is to find how many distinct straight lines can be formed using a given number of points on a plane. This concept is useful for competitive exams like CAT, XAT, SSC, and NTSE.

🔹 Basic Concept: No Three Points are Collinear

If no three points are collinear, then any two points will uniquely form a line. So, the number of lines formed from n such points is:

\[ \text{Number of lines} = \binom{n}{2} = \frac{n(n-1)}{2} \]

This is the maximum number of lines that can be formed from n points.

Example 1:

If there are 5 points and no three are collinear, then:

\[ \binom{5}{2} = \frac{5 \cdot 4}{2} = 10 \text{ lines} \]

🔹 Concept: Some Points are Collinear

If some points are collinear, they lie on the same line. So instead of forming multiple lines, they contribute only one line.

Let's say m points are collinear. Then the total number of lines is:

\[ \binom{n}{2} - \binom{m}{2} + 1 = \frac{n(n-1)}{2} - \frac{m(m-1)}{2} + 1 \]

Example 2:

Out of 7 points, 4 are collinear. Find total number of lines.

\[ \text{Total lines} = \binom{7}{2} - \binom{4}{2} + 1 = 21 - 6 + 1 = 16 \]

🔹 Generalized Concept for Multiple Collinear Groups

If there are multiple sets of collinear points, say m, p, q... collinear points in separate groups, the formula becomes:

\[ \binom{n}{2} - \left[ \binom{m}{2} + \binom{p}{2} + \binom{q}{2} + \dots \right] + (\text{number of such groups}) \]

Example 3:

In a plane, 10 points are given, out of which 4 are collinear and 3 are collinear in another set. Find total number of lines.

\[ \binom{10}{2} - \binom{4}{2} - \binom{3}{2} + 2 = 45 - 6 - 3 + 2 = 38 \]

📌 Final Notes

  • If all n points are collinear, only 1 line is formed.
  • If no three points are collinear, maximum lines = \( \frac{n(n-1)}{2} \)
  • Always subtract lines from collinear subsets and add 1 line per collinear group.
Practice Questions
Number of Lines from n Points – Practice Questions | Geometry – CAT/XAT

📐 Number of Lines from n Points – Practice Questions for CAT/XAT

Click below to reveal answers and explanations. Concept based on combinations and collinear point deductions.



1) From 6 points on a plane, where 3 points are collinear, how many distinct lines can be formed?

  • (a) 12
  • (b) 13
  • (c) 14
  • (d) 15
🔽 Show Answer

Answer: (b) 13

Solution: \( \binom{6}{2} - \binom{3}{2} + 1 = 15 - 3 + 1 = 13 \)

2) If no three of the 10 points are collinear, how many distinct lines can be formed?

  • (a) 40
  • (b) 44
  • (c) 45
  • (d) 48
🔽 Show Answer

Answer: (c) 45

Solution: \( \binom{10}{2} = \frac{10 \cdot 9}{2} = 45 \)

3) From 6 points on a plane, where 4 and 3 points are collinear in two separate groups, how many lines can be formed?

  • (a) 6
  • (b) 7
  • (c) 8
  • (d) 9
🔽 Show Answer

Answer: (c) 8

Solution: \( \binom{6}{2} - \binom{4}{2} - \binom{3}{2} + 2 = 15 - 6 - 3 + 2 = 8 \)

4) If no three of the 14 points are collinear, how many lines can be formed?

  • (a) 90
  • (b) 91
  • (c) 92
  • (d) 105
🔽 Show Answer

Answer: (b) 91

Solution: \( \binom{14}{2} = \frac{14 \cdot 13}{2} = 91 \)

5) From 13 points on a plane, where 4 and 3 are collinear in two different lines, how many distinct lines can be drawn?

  • (a) 69
  • (b) 70
  • (c) 71
  • (d) 72
🔽 Show Answer

Answer: (c) 71

Solution: \( \binom{13}{2} - \binom{4}{2} - \binom{3}{2} + 2 = 78 - 6 - 3 + 2 = 71 \)

6) If no three of the 7 points are collinear, how many lines can be formed?

  • (a) 21
  • (b) 20
  • (c) 22
  • (d) 19
🔽 Show Answer

Answer: (a) 21

Solution: \( \binom{7}{2} = \frac{7 \cdot 6}{2} = 21 \)

7) From 8 points on a plane, where 3 are collinear, how many lines can be formed?

  • (a) 27
  • (b) 26
  • (c) 28
  • (d) 25
🔽 Show Answer

Answer: (a) 27

Solution: \( \binom{8}{2} - \binom{3}{2} + 1 = 28 - 3 + 1 = 26 \)

8) From 11 points, where 5 are collinear, how many distinct lines can be formed?

  • (a) 50
  • (b) 51
  • (c) 52
  • (d) 53
🔽 Show Answer

Answer: (b) 51

Solution: \( \binom{11}{2} - \binom{5}{2} + 1 = 55 - 10 + 1 = 46 \)

9) From 12 points, where 3 and 4 are collinear in two groups, how many lines are possible?

  • (a) 64
  • (b) 66
  • (c) 67
  • (d) 68
🔽 Show Answer

Answer: (c) 67

Solution: \( \binom{12}{2} - \binom{3}{2} - \binom{4}{2} + 2 = 66 - 3 - 6 + 2 = 59 \)

10) If all 9 points are collinear, how many lines can be formed?

  • (a) 36
  • (b) 9
  • (c) 1
  • (d) 0
🔽 Show Answer

Answer: (c) 1

Solution: All points are collinear ⇒ only 1 line.

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