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Dividing Rectangles & Parallelograms into Minimum Number of Shapes

Geometry-Mensuration
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Dividing Rectangles & Parallelograms into Minimum Number of Shapes

Minimum Division of Rectangle & Parallelogram – Geometry Explained

Dividing Rectangles & Parallelograms into Minimum Number of Shapes

1. Rectangle of Size \( m \times n \) into Minimum Number of Identical Squares

To divide a rectangle of dimensions \( m \times n \) into the minimum number of identical squares:

  • Find HCF of \( m \) and \( n \): let it be \( H = \text{HCF}(m, n) \)
  • The side of each square is \( H \)
  • The total number of squares is:
\[ \text{Number of squares} = \frac{m \times n}{H^2} \]

2. Rectangle of Size \( m \times n \) into Non-Identical Squares (By Euclidean Algorithm)

This method gives the minimum number of non-identical squares using the process of repeated subtraction/division:

  • Each step gives a square of size equal to the remainder
  • The total number of squares is the sum of all quotients obtained during division
Use the Euclidean algorithm: count how many times the smaller side goes into the larger, then repeat on the remainder.

3. Parallelogram of Size \( m \times n \) into Minimum Number of Identical Rhombuses

Very similar to rectangle-to-square logic. If the sides are \( m \) and \( n \):

  • Find \( H = \text{HCF}(m, n) \)
  • Each rhombus will be of side \( H \)
  • Number of rhombuses = \( \frac{m \times n}{H^2} \)

4. Parallelogram with Angle = 60° Divided into Equilateral Triangles

When a parallelogram has 60° internal angles, each rhombus can be split into 2 equilateral triangles.

  • Step 1: Use the HCF logic to find number of rhombuses
  • Step 2: Multiply by 2 to get number of equilateral triangles
\[ \text{Number of equilateral triangles} = 2 \times \left( \frac{m \times n}{H^2} \right) \]
Use this formula only when the angle of the parallelogram is 60°.
Quick Summary:
  • Identical shape division → Use HCF
  • Non-identical shape division → Use quotient sum from Euclidean Division
  • Equilateral triangles = 2 × rhombuses (only if angle = 60°)
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